College of Admission Tests Multan

Linear and other Functions

Solve the question of and select the option from the choices A through D/E. Check your Answer and view the explanation.

Question: 10

What equation is perpendicular to y = 5 2 x + 12 and passes through (2,5)?
  • y = 5 2 x + 22 5
  • y = 2 5 x + 27 5
  • y = 2 5 x + 29 5
  • y = 2 5 x + 21 5
  • y = 4 5 x + 26 5

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Correct Answer: C

First find the reciprocal of the slope of the given function.

m 2 = 1 m 1

m 2 = 2 5

The perpendicular function is:

y = 2 5 x + c

Now we must find the constant, c, by using the given point that the perpendicular crosses.

5 = 2 5 ( 2 ) + c

solve for c:

c = 29 5

y = 2 5 x + 29 5